Question

Let \(tan^{-1}y=tan^{-1}x+tan^{-1}(\frac{2x}{1-x^2})\). Then y is:

• A. \(\frac{3x-x^3}{1-3x^2}\)
• B. \(\frac{3x+x^3}{1-3x^2}\)
• C. \(\frac{3x-x^3}{1+3x^2}\)
• D. \(\frac{3x+x^3}{1+3x^2}\)

Answer 1

The Correct Option is A

The correct option is (A):\(\frac{3x-x^3}{1-3x^2}\)