List-I | List-II | ||
(P) | The value of d (H0) is | (1) | \(\sqrt3\) |
(Q) | The distance of the point (0,1,2) from H0 is | (2) | \(\frac{1}{\sqrt3}\) |
(R) | The distance of origin from H0 is | (3) | 0 |
(S) | The distance of origin from the point of intersection of planes y = z, x = 1, and H0 is | (4) | \(\sqrt2\) |
(5) | \(\frac{1}{\sqrt2}\) |
The correct option is (B).
The normal vector of the plane parallel to lines \( l_1 \) and \( l_2 \) is:
\[ \begin{vmatrix} i & j & k \\ 1 & 1 & 1 \\ 1 & 0 & 1 \end{vmatrix} = \hat{j}(1) - \hat{j}(1-1) + \hat{k}(-1) \]
\[ = \hat{i} - \hat{j} \]
\[ H_0 : x - z = c \quad \text{where} \quad (0, 0, 0) \]
\[ \Rightarrow c = 0 \]
\[ H_0 : x - z = 0 \]
(P) The distance of point (0, 1, -1) from \( H_0 \) is:
\[ d(H_0) = \left| \frac{0 - (-1)}{\sqrt{2}} \right| = \frac{1}{\sqrt{2}} \quad \Rightarrow \quad P \rightarrow 5 \]
(Q) The distance from the point (0, 2, 0) to the plane is:
\[ d = \left| \frac{0 - 2}{\sqrt{2}} \right| = \sqrt{2} \quad \Rightarrow \quad Q \rightarrow 4 \]
(R) The distance from the origin to the plane is:
\[ d = \left| \frac{0}{\sqrt{2}} \right| = 0 \quad \Rightarrow \quad S \rightarrow 3 \]
(S) The point of intersection is (1, 1, 1):
\[ \Rightarrow S \rightarrow 1 \]
Distance is:
\[ d = \sqrt{1 + 1 + 1} = \sqrt{3} \]
Match the LIST-I with LIST-II
LIST-I (Expressions) | LIST-II (Values) | ||
---|---|---|---|
A. | \( i^{49} \) | I. | 1 |
B. | \( i^{38} \) | II. | \(-i\) |
C. | \( i^{103} \) | III. | \(i\) |
D. | \( i^{92} \) | IV. | \(-1\) |
Choose the correct answer from the options given below:
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