Question:

Let G be a group of order 39 such that it has exactly one subgroup of order 3 and exactly one subgroup of order 13. Then, which one of the following statements is TRUE ?

Updated On: Aug 13, 2024
  • G is necessarily cyclic
  • G is abelian but need not be cyclic
  • G need not be abelian
  • G has 13 elements of order 13
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The correct option is (A) : G is necessarily cyclic.
Was this answer helpful?
0
0