Question:

Let $f : \bullet \to \bullet $ satisfy $f (x) f ( y) = f (xy) $ for all real numbers $x$ and $y$. If $f (2)= 4$, then $f \left( \frac{1}{2} \right) = $

Updated On: Jun 7, 2024
  • 0
  • $\frac{1}{4}$
  • $\frac{1}{2}$
  • 1
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The Correct Option is B

Solution and Explanation

Given, $f: \bullet \rightarrow \bullet$ $f(x) f(y)=f(x y)$ ...(i) On taking $x=1,\, y=1$ $f()1 f( 1 )=f( 1 \cdot 1 )=f( 1 )^{2}=f( 1 )=f( 1 )= 1$ Now, $x=2,\, y=\frac{1}{2}$, then from E (i) $f(2) f\left(\frac{1}{2}\right)=f\left(2 \cdot \frac{1}{2}\right)$ $\Rightarrow 4 \cdot f\left(\frac{1}{2}\right)=f(1) [\because f(2)=4]$ $\Rightarrow f\left(\frac{1}{2}\right)=\frac{1}{4} f(1)$ On putting the value of $f(1)$, $\Rightarrow f\left(\frac{1}{2}\right)=\frac{1}{4} \cdot 1 =\frac{ 1 }{4}$
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions