Question:

Let $f : \mathbb{R} \to \mathbb{R}$ be given by $f(x) = \tan x$. Then $f^{-1}(1)$ is:

Updated On: Dec 26, 2024
  • $\frac{\pi}{4}$
  • $n\pi + \frac{\pi}{4}; \, n \in \mathbb{Z}$
  • $\frac{\pi}{3}$
  • $n\pi + \frac{\pi}{3}; \, n \in \mathbb{Z}$
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The Correct Option is A

Solution and Explanation

The function $\tan x$ is periodic with period $\pi$.

The principal value of $\tan^{-1}(1)$ is $x = \frac{\pi}{4}$. 

Hence, $f^{-1}(1) = \frac{\pi}{4}$. 

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