Question:
Let f : [1, 2] → \(\R\) be the function defined by
\(f(t)=\int^t_1\sqrt{x^2e^{x^2}-1}\ dx.\)
Then the arc length of the graph of f over the interval [1, 2] equals
Let f : [1, 2] → \(\R\) be the function defined by
\(f(t)=\int^t_1\sqrt{x^2e^{x^2}-1}\ dx.\)
Then the arc length of the graph of f over the interval [1, 2] equals
\(f(t)=\int^t_1\sqrt{x^2e^{x^2}-1}\ dx.\)
Then the arc length of the graph of f over the interval [1, 2] equals
Updated On: Oct 1, 2024
- \(e^2-\sqrt{e}\)
- \(e-\sqrt{e}\)
- e2 - e
- e2 - 1
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The Correct Option is A
Solution and Explanation
The correct option is (A) : \(e^2-\sqrt{e}\).
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