Question:
Let π¦ = π¦(π₯) be a solution curve of the differential equation
\(π₯ \frac{ππ¦}{dπ₯} = π¦ \) ln ( \(\frac{y}{x}\) ) , π¦ > π₯ > 0.
If π¦(1) = π 2 and π¦(2) = πΌ, then the value of \(\frac{ππ¦}{ππ₯}\) at (2, πΌ) is equal to
Let π¦ = π¦(π₯) be a solution curve of the differential equation
\(π₯ \frac{ππ¦}{dπ₯} = π¦ \) ln ( \(\frac{y}{x}\) ) , π¦ > π₯ > 0.
If π¦(1) = π 2 and π¦(2) = πΌ, then the value of \(\frac{ππ¦}{ππ₯}\) at (2, πΌ) is equal to
\(π₯ \frac{ππ¦}{dπ₯} = π¦ \) ln ( \(\frac{y}{x}\) ) , π¦ > π₯ > 0.
If π¦(1) = π 2 and π¦(2) = πΌ, then the value of \(\frac{ππ¦}{ππ₯}\) at (2, πΌ) is equal to
Updated On: Oct 1, 2024
- Ξ±
- \(\frac{Ξ±}{2}\)
- 2Ξ±
- \(\frac{3Ξ±}{2}\)
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The Correct Option is D
Solution and Explanation
The correct option is (D): \(\frac{3Ξ±}{2}\)
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