Let \(\beta\) be a real number Consider the
\(matrix\ A=\begin{pmatrix}\beta & 0 & 1 \\2 & 1 & -2 \\3 & 1 & -2\end{pmatrix}If A^7-(\beta-1) A^6-\beta A^5\) is a singular matrix, then the value of \(9 \beta\) is _____
The given equation is:
\(|A|^5 |A^2 - (\beta - 1) A - \beta| = 0\)
From the equation, we know that if \( |A| \neq 0 \), we can simplify the equation to:
\(A^2 - (\beta - 1) A - \beta = 0\)
Now, factor the expression:
\(\Rightarrow |A + 1| |A - \beta| = 0\)
Since \( |A + 1| \neq 0 \) (we assume \( A \neq -1 \)), we get:
\(|A - \beta| = 0\)
This implies:
\(A = \beta\)
Now, solving for \( \beta \), we get:
\(\beta = \frac{1}{3} \Rightarrow 9\beta = 3\)
Thus, the value of \( \beta \) is \( \frac{1}{3} \), and \( 9\beta = 3 \).
Let \[ f(x)=\int \frac{7x^{10}+9x^8}{(1+x^2+2x^9)^2}\,dx \] and $f(1)=\frac14$. Given that 
Let $ P(x_1, y_1) $ and $ Q(x_2, y_2) $ be two distinct points on the ellipse $$ \frac{x^2}{9} + \frac{y^2}{4} = 1 $$ such that $ y_1 > 0 $, and $ y_2 > 0 $. Let $ C $ denote the circle $ x^2 + y^2 = 9 $, and $ M $ be the point $ (3, 0) $. Suppose the line $ x = x_1 $ intersects $ C $ at $ R $, and the line $ x = x_2 $ intersects $ C $ at $ S $, such that the $ y $-coordinates of $ R $ and $ S $ are positive. Let $ \angle ROM = \frac{\pi}{6} $ and $ \angle SOM = \frac{\pi}{3} $, where $ O $ denotes the origin $ (0, 0) $. Let $ |XY| $ denote the length of the line segment $ XY $. Then which of the following statements is (are) TRUE?
A matrix is a rectangular array of numbers, variables, symbols, or expressions that are defined for the operations like subtraction, addition, and multiplications. The size of a matrix is determined by the number of rows and columns in the matrix.
