Question:

Let (𝑋, π‘Œ, 𝑍) be a random vector having the joint probability density function
\(f(x,y, z) =\begin{cases} \frac{1}{2\,xy}, & \quad \text{if }0<z<y<x<1.\\ \frac{1}{2x^2}, & \quad if\,0<z<x<y<2x<2,\\0, & \quad\,\,Otherwise.\end{cases}\)
Then, which one of the following statements is FALSE?

Updated On: Oct 1, 2024
  • \(𝑃(𝑍 < π‘Œ < 𝑋) = \frac{1}{2}\)
  • 𝑃(𝑋 < π‘Œ < 𝑍) = 0
  • 𝐸(min{𝑋, π‘Œ}) =\(\frac{1}{4}\)
  • π‘‰π‘Žπ‘Ÿ (π‘Œ | 𝑋 = \(\frac{1}{2}\) ) = \(\frac{1}{12}\)
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The Correct Option is C

Solution and Explanation

The correct option is (C): 𝐸(min{𝑋, π‘Œ}) =\(\frac{1}{4}\)
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