Question:
Let π be a random variable having the probability density function
\(f(x) =\begin{cases} \frac{x}{2} & \quad \text{if }0<x<2,\\ 0, & \quad Otherwise \end{cases}\)
Then, πππ (ln ( \(\frac{2}{x}\) )) equals ________
Let π be a random variable having the probability density function
\(f(x) =\begin{cases} \frac{x}{2} & \quad \text{if }0<x<2,\\ 0, & \quad Otherwise \end{cases}\)
Then, πππ (ln ( \(\frac{2}{x}\) )) equals ________
\(f(x) =\begin{cases} \frac{x}{2} & \quad \text{if }0<x<2,\\ 0, & \quad Otherwise \end{cases}\)
Then, πππ (ln ( \(\frac{2}{x}\) )) equals ________
Updated On: Oct 1, 2024
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Correct Answer: 0.25
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The correct answer is: 0.25
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