Question:
Let \(A+B=\begin{bmatrix} 4&1&4\\1&4&4 \end{bmatrix}\)and \(B=\begin{bmatrix} 1&0&-2\\-1&3&0 \end{bmatrix}\), then A=
Let \(A+B=\begin{bmatrix} 4&1&4\\1&4&4 \end{bmatrix}\)and \(B=\begin{bmatrix} 1&0&-2\\-1&3&0 \end{bmatrix}\), then A=
Updated On: Jun 10, 2024
- \(\begin{bmatrix} 3&1&2\\0&3&4 \end{bmatrix}\)
- \(\begin{bmatrix} 5&1&2\\0&7&4 \end{bmatrix}\)
- \(\begin{bmatrix} 3&-1&-2\\2&1&4 \end{bmatrix}\)
- \(\begin{bmatrix} 5&1&6\\2&1&4 \end{bmatrix}\)
- \(\begin{bmatrix} 3&1&6\\2&1&4 \end{bmatrix}\)
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The Correct Option is
Solution and Explanation
The correct option is (E): \(\begin{bmatrix} 3&1&6\\2&1&4 \end{bmatrix}\)
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