We are given the following information:
\[
P(A/B) = \frac{1}{2}, \quad P(B/A) = \frac{1}{3}, \quad P(A \cap B) = \frac{1}{6}
\]
Step 1: Find \( P(A) \) and \( P(B) \)
We use the definition of conditional probability to express \( P(A/B) \) and \( P(B/A) \):
\[
P(A/B) = \frac{P(A \cap B)}{P(B)} \quad \Rightarrow \quad \frac{1}{2} = \frac{\frac{1}{6}}{P(B)} \quad \Rightarrow \quad P(B) = \frac{1}{3}
\]
Now, using the other conditional probability:
\[
P(B/A) = \frac{P(A \cap B)}{P(A)} \quad \Rightarrow \quad \frac{1}{3} = \frac{\frac{1}{6}}{P(A)} \quad \Rightarrow \quad P(A) = \frac{1}{2}
\]
Step 2: Check the Independence Condition
For events A and B to be independent, the following condition must hold:
\[
P(A \cap B) = P(A) \cdot P(B)
\]
Substituting the values of \( P(A) \) and \( P(B) \):
\[
P(A \cap B) = \frac{1}{2} \cdot \frac{1}{3} = \frac{1}{6}
\]
Since this is true, we can conclude that A and B are independent.
Step 3: Calculate \( P(A \cup B) \)
The formula for the union of two events is:
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B)
\]
Substitute the known values:
\[
P(A \cup B) = \frac{1}{2} + \frac{1}{3} - \frac{1}{6} = \frac{3}{6} + \frac{2}{6} - \frac{1}{6} = \frac{2}{3}
\]
So, option (B) is correct.
Step 4: Find \( P(A' \cap B) \)
The probability \( P(A' \cap B) \) is given by:
\[
P(A' \cap B) = P(B) - P(A \cap B) = \frac{1}{3} - \frac{1}{6} = \frac{1}{6}
\]
So, option (C) is correct.
Conclusion
Since we have established that A and B are independent, the correct answer is:
\[
\text{A and B are not independent}
\]
Thus, the correct answer is (A).