Let A and B be sets. \[A \cap X = B \cap X = \varnothing \quad \text{and} \quad A \cup X = B \cup X \quad \text{for some set } X,\ \text{find the relation between } A \text{ and } B.\]
We are given the following conditions:
1. \( A \cap X = B \cap X = \varnothing \) (The intersection of sets \( A \) and \( B \) with \( X \) is the empty set.)
2. \( A \cup X = B \cup X \) (The union of \( A \) with \( X \) is equal to the union of \( B \) with \( X \).) From the first condition, \( A \cap X = B \cap X = \varnothing \), we can conclude that neither \( A \) nor \( B \) shares any elements with \( X \).
Therefore, \( A \) and \( B \) must be disjoint with respect to \( X \).
From the second condition, \( A \cup X = B \cup X \), we can infer that the sets \( A \) and \( B \) must be identical because the union with \( X \) does not change the overall result. If the union of two sets with a third set is the same, the two sets themselves must be equal.
Therefore, \( A = B \). Thus, the correct answer is \( \boxed{(a) \, A = B} \).
Let $A = \{5n - 4n - 1 : n \in \mathbb{N}\}$ and $B = \{16(n - 1): n \in \mathbb{N}\}$ be sets. Then:
Let \( A = (1, 2, 3, \dots, 20) \). Let \( R \subseteq A \times A \) such that \( R = \{(x, y) : y = 2x - 7 \} \). Then the number of elements in \( R \) is equal to:
A remote island has a unique social structure. Individuals are either "Truth-tellers" (who always speak the truth) or "Tricksters" (who always lie). You encounter three inhabitants: X, Y, and Z.
X says: "Y is a Trickster"
Y says: "Exactly one of us is a Truth-teller."
What can you definitively conclude about Z?
Consider the following statements followed by two conclusions.
Statements: 1. Some men are great. 2. Some men are wise.
Conclusions: 1. Men are either great or wise. 2. Some men are neither great nor wise. Choose the correct option: