We compute:
\[
A \times B = \{(1,1),(1,2),(1,3),(2,1),(2,2),(2,3),(5,1),(5,2),(5,3),(6,1),(6,2),(6,3)\}
\]
\[
B \times A = \{(1,1),(1,2),(1,5),(1,6),(2,1),(2,2),(2,5),(2,6),(3,1),(3,2),(3,5),(3,6)\}
\]
Their intersection: only elements common to both
\[
C = \{(1,1),(1,2),(2,1),(2,2)\}
\]
Thus, (2,3) ∉ C → it's the incorrect one.