The change in length is given by:
\[
\Delta L = \alpha L \Delta T
\]
where \(\Delta L / L = 0.2%\), \(\Delta T = 100^\circ C\). Solving for \(\alpha\), we find:
\[
\alpha = \frac{0.2%}{100} = 2 \times 10^{-5} \, \text{per}^\circ C
\]
Thus, the correct answer is \(2 \times 10^{-5}\) per °C.