Question:
$l,m,n$ the real, $l\, \ne\, m$, roots of the equation $(l -m) x^2- 5(l + m)x -2(l- m) = 0$ are.
$l,m,n$ the real, $l\, \ne\, m$, roots of the equation $(l -m) x^2- 5(l + m)x -2(l- m) = 0$ are.
Updated On: Jul 6, 2022
- real and equal
- complex
- real and unequal
- none of these
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The Correct Option is C
Solution and Explanation
Discriminant $= 25 (l + m)^2 + 8 (l - m)^2 > 0$
$\therefore$ roots are real and unequal.
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Concepts Used:
Complex Numbers and Quadratic Equations
Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.
Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.
