Question

Ketoxime on reduction with sodium in ethanol forms

• A. 1\(^\circ\) amine
• B. 2\(^\circ\) amine
• C. 1\(^\circ\) and 2\(^\circ\) amine
• D. 3\(^\circ\) amine

Hint:

The reduction of ketoximes with sodium in ethanol leads to the formation of primary amines.

Answer 1

The Correct Option is A

Step 1: Understanding the reduction of ketoxime.
Ketoxime (R\(_2\)C=NOH) can be reduced by sodium in ethanol to form a primary amine (R\(_2\)NH). Sodium reduces the oxime group (-NOH) to an amine group (-NH\(_2\)).

Step 2: Analyzing the options.
(A) 1\(^\circ\) amine: Correct — The reduction of ketoxime with sodium in ethanol forms a primary amine.
(B) 2\(^\circ\) amine: This is incorrect. A secondary amine is not formed in this reaction.
(C) 1\(^\circ\) and 2\(^\circ\) amine: This is incorrect. Only a primary amine is formed.
(D) 3\(^\circ\) amine: This is incorrect. A tertiary amine is not formed in this reaction.

Step 3: Conclusion.
The correct product is a 1\(^\circ\) amine, so the answer is (A) 1\(^\circ\) amine.