The standard electrode potentials are given as:
\[
E^\circ_{Fe^{3+}/Fe^{2+}} = 0.771 \, \text{V}, \quad E^\circ_{Br_2/Br^-} = 1.09 \, \text{V}.
\]
Since the reduction potential of \( Br_2/Br^- \) is higher than \( Fe^{3+}/Fe^{2+} \), bromide ions cannot be oxidized by ferric ions.