Question:
Iodoform test can differentiate between
A. Methanol and Ethanol
B. $\text{CH_3\text{COOH}$ and $\text{CH}_3\text{CH}_2\text{COOH}$
C. Cyclohexene and cyclohexanone
D. Diethyl ether and Pentan-3-one
E. Anisole and acetone}
Iodoform test can differentiate between
A. Methanol and Ethanol
B. $\text{CH_3\text{COOH}$ and $\text{CH}_3\text{CH}_2\text{COOH}$
C. Cyclohexene and cyclohexanone
D. Diethyl ether and Pentan-3-one
E. Anisole and acetone}
A. Methanol and Ethanol
B. $\text{CH_3\text{COOH}$ and $\text{CH}_3\text{CH}_2\text{COOH}$
C. Cyclohexene and cyclohexanone
D. Diethyl ether and Pentan-3-one
E. Anisole and acetone}
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If both or neither compound gives a positive result, the test fails to differentiate them.
Updated On: Feb 5, 2026
- B, C & E Only
- A, B & E Only
- A & E Only
- A & D Only
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The Correct Option is C
Solution and Explanation
Iodoform test distinguishes compounds containing $CH_3CO-$ or $CH_3CH(OH)-$ group.
A. Ethanol (Positive), Methanol (Negative). Differentiates.
B. Both are carboxylic acids, neither is positive. Does not differentiate.
C. Both are negative. Cyclohexanone (no methyl ketone) and Cyclohexene (alkene). Does not differentiate.
D. Diethyl ether (negative). Pentan-3-one ($CH_3CH_2COCH_2CH_3$) is negative. Does not differentiate.
E. Acetone ($CH_3COCH_3$) is positive. Anisole (negative). Differentiates.
The test differentiates pairs A and E.
A. Ethanol (Positive), Methanol (Negative). Differentiates.
B. Both are carboxylic acids, neither is positive. Does not differentiate.
C. Both are negative. Cyclohexanone (no methyl ketone) and Cyclohexene (alkene). Does not differentiate.
D. Diethyl ether (negative). Pentan-3-one ($CH_3CH_2COCH_2CH_3$) is negative. Does not differentiate.
E. Acetone ($CH_3COCH_3$) is positive. Anisole (negative). Differentiates.
The test differentiates pairs A and E.
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