Interpret the given diagrams A and B. Enlist the changes occurring during inspiration and expiration.
The given diagrams represent pulmonary ventilation, specifically inspiration (A) and expiration (B).
Diagram A - Inspiration (Inhalation):
- The diaphragm contracts and moves downward.
- The rib cage expands as the intercostal muscles contract.
- The volume of the thoracic cavity increases, reducing pressure inside the lungs.
- Air rushes into the lungs due to the pressure difference.
Diagram B - Expiration (Exhalation):
- The diaphragm relaxes and moves upward.
- The rib cage moves downward and inward as intercostal muscles relax.
- The volume of the thoracic cavity decreases, increasing pressure inside the lungs.
- Air is pushed out of the lungs.
List - I | List – II | ||
A. | Residual Volume | i. | Maximum volume of air that can be breathed in after forced expiration |
B. | Vital Capacity | ii. | Volume of air inspired or expired during normal respiration |
C. | Expiratory Capacity | iii. | Volume of air remaining in lungs after forcible expiration |
D. | Tidal Volume | iv. | Total volume of air expired after normal inspiration |
The slope of the tangent to the curve \( x = \sin\theta \) and \( y = \cos 2\theta \) at \( \theta = \frac{\pi}{6} \) is ___________.
Solve the following L.P.P. by graphical method:
Maximize:
\[ z = 10x + 25y. \] Subject to: \[ 0 \leq x \leq 3, \quad 0 \leq y \leq 3, \quad x + y \leq 5. \]