Question:

Intensity of gravitational field inside the hollow spherical shell is

Updated On: Jun 21, 2022
  • Variable
  • minimum
  • maximum
  • zero
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

It's because the pull from every direction is exactly the same. This is obvious from the center, but as you move to one side, you're closer to that side, which increases its pull, but this is exactly offset by the fact that there's now MORE mass on the other side.
Was this answer helpful?
0
0

Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].