Question

\(\int \frac{dx}{e^{-x}} \)

• A. \( - \frac{1}{e^{-x}} + k \)
• B. \( e^x + k \)
• C. \( \frac{1}{e^{-x}} + k \)
• D. \( -e^{-x} + k \)

Hint:

When integrating exponentials of the form \( e^x \), the result is simply \( e^x + k \).

Answer 1

The Correct Option is B

We need to evaluate: \[ I = \int \frac{dx}{e^{-x}} \] This simplifies to: \[ I = \int e^{x} dx \] The integral of \( e^x \) is \( e^x \), so the solution is: \[ I = e^x + k \]