Question:

abf(x)dx \int_a^b f(x) \, dx is equal to:

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In definite integrals, substitution with a linear transformation often results in limits being swapped, simplifying the integral.
Updated On: Jan 18, 2025
  • abf(ax)dx \int_a^b f(a - x) \, dx
  • abf(a+bx)dx \int_a^b f(a + b - x) \, dx
  • abf(x(a+b))dx \int_a^b f(x - (a + b)) \, dx
  • abf((ax)+(bx))dx \int_a^b f((a - x) + (b - x)) \, dx
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The Correct Option is B

Solution and Explanation

To evaluate the transformation, let u=a+bx u = a + b - x

Then: dudx=1ordx=du. \frac{du}{dx} = -1 \quad \text{or} \quad dx = -du. When x=a x = a , u=b u = b ; and when x=b x = b , u=a u = a

The integral becomes: abf(x)dx=baf(a+bu)(du). \int_a^b f(x) \, dx = \int_b^a f(a + b - u) (-du).  

Reversing the limits of integration, the negative sign is removed: abf(x)dx=abf(a+bx)dx. \int_a^b f(x) \, dx = \int_a^b f(a + b - x) \, dx.

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