Question:

\( \int_{-a}^a f(x) \, dx = 0 \), if:

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Odd functions are symmetric about the origin, and their integrals over symmetric intervals cancel out.
Updated On: Jan 28, 2025
  • \( f(-x) = f(x) \)
  • \( f(-x) = -f(x) \)
  • \( f(a - x) = f(x) \)
  • \( f(a - x) = -f(x) \)
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The Correct Option is B

Solution and Explanation

If \( f(-x) = -f(x) \), the function is odd. For odd functions, the integral over a symmetric interval \( [-a, a] \) is: \[ \int_{-a}^a f(x) \, dx = 0. \] This is because the areas above and below the x-axis cancel out.
Final Answer: \( \boxed{f(-x) = -f(x)} \)
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