Question:

Instead of turning right at the end if he took left and walked 20 km, what is the shortest distance to his starting point?

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Translate every turn into a direction on the \(xy\)-plane and keep running coordinates. Then use the Pythagorean theorem for the straight-line distance.
Updated On: Sep 3, 2025
  • \(3\sqrt{7}\) km
  • \(2\sqrt{5}\) km
  • \(7\sqrt{2}\) km
  • \(5\sqrt{2}\) km
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The Correct Option is D

Solution and Explanation

Path with coordinates:
Start at \(O(0,0)\). Take \(+x\) east, \(+y\) north.
- Walk 25 km west \(\Rightarrow (-25,0)\).
- Left (to south) 15 km \(\Rightarrow (-25,-15)\).
- Left (to east) 30 km \(\Rightarrow (5,-15)\).
- Now take left (to north) and walk 20 km \(\Rightarrow (5,5)\).
Distance from start:
\[ d=\sqrt{(5-0)^2+(5-0)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ \text{km}. \] \[ \boxed{5\sqrt{2}\ \text{km}} \]
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