Information for a proposed greenfield project is provided in the table. The discounted cash flow for the fourth year is Rs \(\underline{\hspace{1cm}}\) crores (rounded off to one decimal place).

"fourth year" means the fourth year from project initiation (Year 4).
This would be operational year 2 (since plant starts in year 2).
For Year 4 (operational year 2):
$$\text{EBIT} = 120 - 30 - 51.02 = 38.98 \text{ crores}$$ $$\text{Tax} = 0.30 \times 38.98 = 11.69 \text{ crores}$$ $$\text{Net Income} = 38.98 - 11.69 = 27.29 \text{ crores}$$ $$\text{Cash Flow} = 27.29 + 51.02 = 78.31 \text{ crores}$$
$$\text{Discounted Cash Flow} = \frac{78.31}{(1.10)^4} = \frac{78.31}{1.4641} = 53.5 \text{ crores}$$
Answer
The discounted cash flow for the fourth year is 53.5 crores (rounded to one decimal place).
Consider a process with transfer function: \[ G_p = \frac{2e^{-s}}{(5s + 1)^2} \] A first-order plus dead time (FOPDT) model is to be fitted to the unit step process reaction curve (PRC) by applying the maximum slope method. Let \( \tau_m \) and \( \theta_m \) denote the time constant and dead time, respectively, of the fitted FOPDT model. The value of \( \frac{\tau_m}{\theta_m} \) is __________ (rounded off to 2 decimal places).
Given: For \( G = \frac{1}{(\tau s + 1)^2} \), the unit step output response is: \[ y(t) = 1 - \left(1 + \frac{t}{\tau}\right)e^{-t/\tau} \] The first and second derivatives of \( y(t) \) are: \[ \frac{dy(t)}{dt} = \frac{t}{\tau^2} e^{-t/\tau} \] \[ \frac{d^2y(t)}{dt^2} = \frac{1}{\tau^2} \left(1 - \frac{t}{\tau}\right) e^{-t/\tau} \]
Choose the transfer function that best fits the output response to a unit step input change shown in the figure:

An electrical wire of 2 mm diameter and 5 m length is insulated with a plastic layer of thickness 2 mm and thermal conductivity \( k = 0.1 \) W/(m·K). It is exposed to ambient air at 30°C. For a current of 5 A, the potential drop across the wire is 2 V. The air-side heat transfer coefficient is 20 W/(m²·K). Neglecting the thermal resistance of the wire, the steady-state temperature at the wire-insulation interface __________°C (rounded off to 1 decimal place).

GIVEN:
Kinematic viscosity: \( \nu = 1.0 \times 10^{-6} \, {m}^2/{s} \)
Prandtl number: \( {Pr} = 7.01 \)
Velocity boundary layer thickness: \[ \delta_H = \frac{4.91 x}{\sqrt{x \nu}} \]
The first-order irreversible liquid phase reaction \(A \to B\) occurs inside a constant volume \(V\) isothermal CSTR with the initial steady-state conditions shown in the figure. The gain, in kmol/m³·h, of the transfer function relating the reactor effluent \(A\) concentration \(c_A\) to the inlet flow rate \(F\) is:
