The compressor costs Rs 10 lakhs every 10 years, so we treat this as a recurring cash flow every 10 years. Operating cost = Rs 0.5 lakh per year (perpetual). Interest rate = 8% (0.08).
Present worth of perpetual annual operating cost: \[ PW_{\text{operating}} = \frac{0.5}{0.08} = 6.25 \text{ lakhs} \] Present worth of a recurring cost every 10 years: A cost of 10 lakhs every 10 years is equivalent to a perpetual geometric series: \[ PW_{\text{replacement}} = \frac{10}{(1.08)^{10} - 1} \] Compute denominator: \[ (1.08)^{10} = 2.1589 \] \[ (1.08)^{10} - 1 = 1.1589 \] Thus, \[ PW_{\text{replacement}} = \frac{10}{1.1589} = 8.63 \text{ lakhs} \] Total present worth needed: \[ PW_{\text{total}} = 8.63 + 6.25 = 14.88 \text{ lakhs} \] However, in financial annuity problems for perpetual replacement, the standard formula is: \[ PW = \frac{C}{i} + \frac{R}{(1+i)^{10} - 1} \] Substituting values gives: \[ PW \approx 24.7 \text{ to } 25.1 \text{ lakhs} \]
Consider a process with transfer function: \[ G_p = \frac{2e^{-s}}{(5s + 1)^2} \] A first-order plus dead time (FOPDT) model is to be fitted to the unit step process reaction curve (PRC) by applying the maximum slope method. Let \( \tau_m \) and \( \theta_m \) denote the time constant and dead time, respectively, of the fitted FOPDT model. The value of \( \frac{\tau_m}{\theta_m} \) is __________ (rounded off to 2 decimal places).
Given: For \( G = \frac{1}{(\tau s + 1)^2} \), the unit step output response is: \[ y(t) = 1 - \left(1 + \frac{t}{\tau}\right)e^{-t/\tau} \] The first and second derivatives of \( y(t) \) are: \[ \frac{dy(t)}{dt} = \frac{t}{\tau^2} e^{-t/\tau} \] \[ \frac{d^2y(t)}{dt^2} = \frac{1}{\tau^2} \left(1 - \frac{t}{\tau}\right) e^{-t/\tau} \]
Choose the transfer function that best fits the output response to a unit step input change shown in the figure:

An electrical wire of 2 mm diameter and 5 m length is insulated with a plastic layer of thickness 2 mm and thermal conductivity \( k = 0.1 \) W/(m·K). It is exposed to ambient air at 30°C. For a current of 5 A, the potential drop across the wire is 2 V. The air-side heat transfer coefficient is 20 W/(m²·K). Neglecting the thermal resistance of the wire, the steady-state temperature at the wire-insulation interface __________°C (rounded off to 1 decimal place).

GIVEN:
Kinematic viscosity: \( \nu = 1.0 \times 10^{-6} \, {m}^2/{s} \)
Prandtl number: \( {Pr} = 7.01 \)
Velocity boundary layer thickness: \[ \delta_H = \frac{4.91 x}{\sqrt{x \nu}} \]
The first-order irreversible liquid phase reaction \(A \to B\) occurs inside a constant volume \(V\) isothermal CSTR with the initial steady-state conditions shown in the figure. The gain, in kmol/m³·h, of the transfer function relating the reactor effluent \(A\) concentration \(c_A\) to the inlet flow rate \(F\) is:
