Question

In Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is \( \frac{\lambda}{4} \), will be

• A. \( \frac{1}{4} \)
• B. \( \frac{1}{2} \)
• C. zero
• D. one

Hint:

In Young’s double-slit experiment, destructive interference occurs when the path difference is an odd multiple of \( \frac{\lambda}{2} \), causing the intensity to be zero.

Answer 1

The Correct Option is C

Step 1: Analyze the condition for constructive and destructive interference.
In Young's double-slit experiment, the intensity of light at any point is a result of constructive or destructive interference. When the path difference is \( \frac{\lambda}{4} \), the waves will be out of phase, resulting in destructive interference.
Step 2: Conclusion.
Thus, the intensity at this point will be zero.
Final Answer: \[ \boxed{0} \]