>
Exams
>
Biology
>
The Root
>
in which plants oxygen is absorbed through aerial
Question:
In which plants oxygen is absorbed through aerial roots?
TS POLYCET - 2021
TS POLYCET
Updated On:
Apr 30, 2024
Mango
Mangroves
Banana
Rose
Hide Solution
Verified By Collegedunia
The Correct Option is
B
Solution and Explanation
The correct option is (B): Mangroves
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on The Root
Who coined the term 'root pressure theory'?
MHT CET - 2024
Biology
The Root
View Solution
When a stem of a plant is cut a few inches above the soil and xylem sap is seen flowing out through the cut end, this exudation is considered evidence for the existence of root pressure. Who proposed the theory of root pressure?
MHT CET - 2024
Biology
The Root
View Solution
The process responsible for facilitating loss of water in liquid form from the tip of grass blades at night and in early morning is
NEET (UG) - 2020
Biology
The Root
View Solution
The product(s) of reaction catalyzed by nitrogenase in root nodules of leguminous plants is/are :
NEET (UG) - 2020
Biology
The Root
View Solution
Sweet potato is a modified
NEET (UG) - 2018
Biology
The Root
View Solution
View More Questions
Questions Asked in TS POLYCET exam
A tangent AB at a point 'A' of a circle of radius 7 cm meets a line through the centre 'C' at a point 'B' so that CB=11 cm, then the length of AB =
TS POLYCET - 2023
Tangent to a Circle
View Solution
△
A
B
C
∼
△
D
E
F
\triangle ABC \sim \triangle DEF
△
A
BC
∼
△
D
EF
and their areas are respectively
81
cm
2
and
225
cm
2
81 \text{ cm}^2 \quad \text{and} \quad 225 \text{ cm}^2
81
cm
2
and
225
cm
2
; if
E
F
=
5
c
m
EF = 5 cm
EF
=
5
c
m
, then
B
C
=
BC=
BC
=
TS POLYCET - 2023
Triangles
View Solution
If
sec
θ
=
2
3
\sec \theta = \frac{2}{\sqrt{3}}
sec
θ
=
3
2
,then
c
o
s
θ
=
cosθ=
cos
θ
=
TS POLYCET - 2023
Trigonometry
View Solution
The value of
tan
2
6
∘
.
tan
6
4
∘
\tan 26^\circ. \tan 64^\circ
tan
2
6
∘
.
tan
6
4
∘
is
TS POLYCET - 2023
Trigonometry
View Solution
In the figure, if AP and AQ are the two tangents to a circle with centre 'O' so that
∠
O
Q
P
=
15
°
∠OQP=15°
∠
OQP
=
15°
, then
∠
Q
A
P
=
∠QAP=
∠
Q
A
P
=
TS POLYCET - 2023
Tangent to a Circle
View Solution
View More Questions