The complex where the conductivity corresponds to a 1:2 electrolyte in aqueous solution is Tetraamminedichlorocobalt(III) chloride.
Explanation:
When tetraamminedichlorocobalt(III) chloride dissolves in water, it dissociates into two ions: [Co(NH3)4Cl2] and Cl-. This dissociation results in the conductivity of a 1:2 electrolyte, where one ion is the complex ion and the other is chloride. The dissociation leads to the production of two ions, thus making the conductivity correspond to a 1:2 electrolyte.
In very high electric field \( E > 10^5 \),
(A) Asymmetric affect disappears
(B) Electrophoretic affect disappears
(C) The ion moves so rapidly that it loses its ionic atmosphere.
(D) The weak electrolyte is completely ionised at all dilutions.