The complex where the conductivity corresponds to a 1:2 electrolyte in aqueous solution is Tetraamminedichlorocobalt(III) chloride.
Explanation:
When tetraamminedichlorocobalt(III) chloride dissolves in water, it dissociates into two ions: [Co(NH3)4Cl2] and Cl-. This dissociation results in the conductivity of a 1:2 electrolyte, where one ion is the complex ion and the other is chloride. The dissociation leads to the production of two ions, thus making the conductivity correspond to a 1:2 electrolyte.
Given below are two statements:
Statement I: Benzene is nitrated to give nitrobenzene, which on further treatment with \( \text{CH}_3\text{COCl} / \text{AlCl}_3 \) will give the product shown. 
Statement II: \( -\text{NO}_2 \) group is a meta-directing and deactivating group.
In the light of the above statements, choose the most appropriate answer from the options given below.
In very high electric field \( E > 10^5 \),
(A) Asymmetric affect disappears
(B) Electrophoretic affect disappears
(C) The ion moves so rapidly that it loses its ionic atmosphere.
(D) The weak electrolyte is completely ionised at all dilutions.