Question

In which of the following, the molecules are arranged in the increasing order of their bond angles?

• A. P\textsubscript{4} < S\textsubscript{6} < O\textsubscript{3} < S\textsubscript{8}
• B. S\textsubscript{6} < O\textsubscript{3} < S\textsubscript{8} < P\textsubscript{4}
• C. O\textsubscript{3} < S\textsubscript{8} < P\textsubscript{4} < S\textsubscript{6}
• D. P\textsubscript{4} < S\textsubscript{6} < S\textsubscript{8} < O\textsubscript{3}

Hint:

Remember: Lone pairs reduce bond angles. Compare molecular shapes and electron pair repulsions.

Answer 1

The Correct Option is D

Bond angle increases with decreasing lone pair-bond pair repulsion and increasing electronegativity and hybridization. P\textsubscript{4} (tetrahedral structure with small angle), S\textsubscript{6} and S\textsubscript{8} (crown-like structures), and O\textsubscript{3} (angular) follow the order of increasing bond angles as given.