Question:
In which of the following cases, there is no change in hybridization of the central atom?
In which of the following cases, there is no change in hybridization of the central atom?
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If a molecule undergoes bonding without increasing the number of hybrid orbitals, its hybridization remains the same.
Updated On: Mar 24, 2025
- \( NH_3 + H^+ \rightarrow NH_4^+ \)
- \( BF_3 + F^- \rightarrow BF_4^- \)
- \( PCl_5 + Cl^- \rightarrow PCl_6^- \)
- \( ClF_3 + F^- \rightarrow ClF_4^- \)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding Hybridization Changes
- \( NH_3 \) has sp\(^3\) hybridization with a lone pair.
- When it gains a proton to form \( NH_4^+ \), the lone pair is replaced by a bonding pair, but the hybridization remains sp\(^3\).
For the other cases:
- \( BF_3 \) (sp\(^2\)) changes to \( BF_4^- \) (sp\(^3\)).
- \( PCl_5 \) (sp\(^3\)d) changes to \( PCl_6^- \) (sp\(^3\)d\(^2\)).
- \( ClF_3 \) (sp\(^3\)d) changes to \( ClF_4^- \) (sp\(^3\)d\(^2\)).
Thus, only in option (1), the hybridization remains unchanged.
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