Step 1: Understanding entropy (\( \Delta S \)).
- Entropy represents the disorder or randomness of a system.
- A positive \( \Delta S \) means increased randomness, while a negative \( \Delta S \) means decreased randomness.
Step 2: Analyzing the given processes.
- (A) Evaporation of water: Liquid to gas transition increases entropy (\( \Delta S>0 \)).
- (B) Gas expansion: Increase in volume increases entropy (\( \Delta S>0 \)).
- (C) Sublimation: Solid to gas transition increases entropy (\( \Delta S>0 \)).
- (D) Formation of \( H_2 \) from \( H \) atoms: Two gas molecules combine into one, decreasing entropy (\( \Delta S<0 \)).
Step 3: Identifying the correct answer.
- Since option (D) represents a decrease in entropy, it is the correct answer.
The standard heat of formation, in kcal/mol, of $Ba^{2+}$ is:
Given: Standard heat of formation of SO₄²⁻(aq) = -216 kcal/mol, standard heat of crystallization of BaSO₄(s) = -4.5 kcal/mol, standard heat of formation of BaSO₄(s) = -349 kcal/mol.
A stream of superheated steam (2 MPa, 300°C) mixes with another stream of superheated steam (2 MPa, 400°C) through a steady-state adiabatic process. The flow rates of the streams are 3 kg/min and 2 kg/min, respectively. This mixture then expands in an adiabatic nozzle to a saturated mixture with quality of 0.77 and 1 kPa. Neglect the velocity at the nozzle entrance and the change in potential energies. The velocity at the nozzle exit (in m/s) is ......... (rounded off to two decimal places).
Use the following data:
At 2 MPa, 300 °C: Specific enthalpy of superheated steam = 3024.2 kJ/kg
At 2 MPa, 400 °C: Specific enthalpy of superheated steam = 3248.4 kJ/kg
At 1 kPa: Specific enthalpy of saturated water = 29.3 kJ/kg
At 1 kPa: Specific enthalpy of saturated vapour = 2513.7 kJ/kg