Question

In very high electric field \( E > 10^5 \), 

(A) Asymmetric affect disappears 
(B) Electrophoretic affect disappears 
(C) The ion moves so rapidly that it loses its ionic atmosphere. 
(D) The weak electrolyte is completely ionised at all dilutions. 
 

• A. (A), (B) and (D) only
• B. (A) and (C) only
• C. (A), (B), (C) and (D)
• D. (B), (C) and (D) only

Hint:

In very high electric fields, the ions move rapidly and their ionic atmosphere disappears, leading to complete ionization of weak electrolytes.

Answer 1

The Correct Option is A

Step 1: Analysis of the high electric field effect.
In very high electric fields, the behavior of ions and electrolytes changes significantly. The effects of electrophoresis (where ions move due to an applied electric field) and asymmetry disappear as the ions move at very high velocities. The ions also lose their ionic atmosphere as they move rapidly. Furthermore, the weak electrolyte tends to ionize completely in very high electric fields.

Step 2: Analysis of options.
- (A) Asymmetric affect disappears: This is true; the ions move symmetrically under a high electric field.
- (B) Electrophoretic affect disappears: This is true as well; the behavior of ions is affected by high electric fields.
- (C) The ion moves so rapidly that it loses its ionic atmosphere: This is true; in high fields, ions can lose their ionic atmosphere.
- (D) The weak electrolyte is completely ionized at all dilutions: This is true because the electric field can break down the electrolyte even at low concentrations.

Step 3: Conclusion.
The correct answer is (1) (A), (B), and (D) only, since all of the mentioned effects are true in a very high electric field.