In triangle ABC, DE is parallel to BC.
AD = 6 cm, DB = 4 cm, AE = 9 cm. We need to find EC.
By the Basic Proportionality Theorem (Thales' Theorem), \(\frac{AD}{DB} = \frac{AE}{EC}\).
\(\frac{6}{4} = \frac{9}{EC}\)
\(EC = \frac{9 \times 4}{6} = \frac{36}{6} = 6\) cm.