Step 1: Understanding the wave equation.
The given wave equation is:
\[ y = 3 \cos \pi (100t - x) \] This is a standard wave equation of the form: \[ y = A \cos(kx - \omega t) \] where \( k \) is the wave number and \( \omega \) is the angular frequency.
Step 2: Identifying the wavelength.
In the equation \( y = 3 \cos \pi (100t - x) \), comparing it with the standard form, we see that \( k = \pi \). The relationship between the wave number \( k \) and the wavelength \( \lambda \) is: \[ k = \frac{2\pi}{\lambda} \] Thus: \[ \pi = \frac{2\pi}{\lambda} \quad \Rightarrow \quad \lambda = 2 \, \text{cm} \] Thus, the correct answer is
(A) 2 cm.
The figure shows a system of two equal masses \( m \) and three massless horizontal springs with spring constants \( k_1 \), \( k_2 \), and \( k_1 \). Ignore gravity. The masses can move only in the horizontal direction, and there is no dissipation. If \( m = 1 \), \( k_1 = 2 \), and \( k_2 = 3 \) (all in appropriate units), the frequencies of the normal modes of the system in the same system of units are:
Calculate the EMF of the Galvanic cell: $ \text{Zn} | \text{Zn}^{2+}(1.0 M) \parallel \text{Cu}^{2+}(0.5 M) | \text{Cu} $ Given: $ E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.763 \, \text{V} $ and $ E^\circ_{\text{Cu}^{2+}/\text{Cu}} = +0.350 \, \text{V} $
Find the values of a, b, c, and d for the following redox equation: $ a\text{I}_2 + b\text{NO} + 4\text{H}_2\text{O} = c\text{HNO}_3 + d\text{HI} $