Question:
In the triangle ABC, MN is parallel to AB. Area of trapezium ABNM is twice the area of triangle CMN. What is ratio of CM : AM ?
In the triangle ABC, MN is parallel to AB. Area of trapezium ABNM is twice the area of triangle CMN. What is ratio of CM : AM ?
Updated On: Jul 31, 2024
- \(\frac{1}{(\sqrt3+1)}\)
- \(\frac{(\sqrt3-1)}{2}\)
- \(\frac{(\sqrt3+1)}{2}\)
- none of these
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The Correct Option is C
Solution and Explanation
The correct option is (C) : \(\frac{(\sqrt3+1)}{2}\).
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