Question

In the series of alphabets given below, which is the missing alphabet series? AX, DU, GR, .............., ML

• A. JO
• B. HQ
• C. JN
• D. IK

Hint:

For two-letter sequences, track the left and right letters separately in numeric form, look for constant steps, and always verify by extending one extra term.

Answer 1

The Correct Option is A

We analyse the two-letter terms by splitting each into its first and second letters because many letter-series progress independently in each position.
Write the alphabet with positions for reference: A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26).
First letters: A, D, G, ?, M.
Convert to positions: 1, 4, 7, ?, 13.
Observe the difference pattern: +3, +3, +3, +3 — a constant step of 3 forward each time.
So the missing first letter position is \(7 + 3 = 10\), which is J.
Second letters: X, U, R, ?, L.
Convert to positions: 24, 21, 18, ?, 12.
Observe the pattern: −3, −3, −3, −6 at the end would be inconsistent, so keep the constant step −3 to maintain uniformity.
Thus the missing second letter position is \(18 - 3 = 15\), which is O.
Combining the two positions gives JO as the missing term.
Quick cross-check: Continue one more step to verify uniformity — after JO (J,O) applying +3 and −3 gives M,L which matches the last given term ML — verification passed.
Therefore, the missing alphabet series is JO.