Step 1: Understanding Rutherford’s Alpha Scattering Experiment
In Rutherford’s alpha scattering experiment, the impact parameter (\( b \)) is defined as the perpendicular distance between the direction of motion of the alpha particle and the center of the nucleus of the atom being targeted.
Step 2: Relation between Impact Parameter and Scattering Angle
The scattering angle (\( \theta \)) is the angle through which the alpha particle deviates from its original path. As per Rutherford’s scattering theory:
Thus, clearly as the impact parameter increases, the scattering angle decreases.
In Rutherford's alpha scattering experiment, the scattering angle of the alpha particle depends on the impact parameter. The impact parameter is the perpendicular distance from the center of the target nucleus to the trajectory of the alpha particle.
As the impact parameter increases, the distance between the alpha particle and the nucleus also increases, meaning the force of interaction becomes weaker. This results in a smaller scattering angle. Therefore, as the impact parameter increases, the scattering angle of the alpha particle decreases.
Thus, the correct answer is that the scattering angle decreases as the impact parameter increases.
Mass Defect and Energy Released in the Fission of \( ^{235}_{92}\text{U} \)
When a neutron collides with \( ^{235}_{92}\text{U} \), the nucleus gives \( ^{140}_{54}\text{Xe} \) and \( ^{94}_{38}\text{Sr} \) as fission products, and two neutrons are ejected. Calculate the mass defect and the energy released (in MeV) in the process.
Given: