Step 1: Understanding Rutherford’s Alpha Scattering Experiment
In Rutherford’s alpha scattering experiment, the impact parameter (\( b \)) is defined as the perpendicular distance between the direction of motion of the alpha particle and the center of the nucleus of the atom being targeted.
Step 2: Relation between Impact Parameter and Scattering Angle
The scattering angle (\( \theta \)) is the angle through which the alpha particle deviates from its original path. As per Rutherford’s scattering theory:
Thus, clearly as the impact parameter increases, the scattering angle decreases.
In Rutherford's alpha scattering experiment, the scattering angle of the alpha particle depends on the impact parameter. The impact parameter is the perpendicular distance from the center of the target nucleus to the trajectory of the alpha particle.
As the impact parameter increases, the distance between the alpha particle and the nucleus also increases, meaning the force of interaction becomes weaker. This results in a smaller scattering angle. Therefore, as the impact parameter increases, the scattering angle of the alpha particle decreases.
Thus, the correct answer is that the scattering angle decreases as the impact parameter increases.
Match the LIST-I with LIST-II
LIST-I (Type of decay in Radioactivity) | LIST-II (Reason for stability) | ||
---|---|---|---|
A. | Alpha decay | III. | Nucleus is mostly heavier than Pb (Z=82) |
B. | Beta negative decay | IV. | Nucleus has too many neutrons relative to the number of protons |
C. | Gamma decay | I. | Nucleus has excess energy in an excited state |
D. | Positron Emission | II. | Nucleus has too many protons relative to the number of neutrons |
Choose the correct answer from the options given below:
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The density of the copper ($^{64}Cu$) nucleus is greater than that of the carbon ($^{12}C$) nucleus.
Reason (R): The nucleus of mass number A has a radius proportional to $A^{1/3}$.
In the light of the above statements, choose the most appropriate answer from the options given below: