in the reaction
MgBr+CH3NH2 Dry ether the number of possible isomers for the organic compound is
In this reaction, ethylmagnesium bromide (CH\(_3\)CH\(_2\)MgBr) reacts with methylamine (CH\(_3\)NH\(_2\)) to form an organic compound X. The reaction proceeds as follows:
The two isomers are:
N-Ethylmethylamine: CH\(_3\)CH\(_2\)NH\(_2\) (ethyl group attached to nitrogen).
N-Methylmethylamine: CH\(_3\)NH\(_2\) (methyl group attached to nitrogen).
Thus, the number of possible isomers for X is 2.
The incorrect statements regarding geometrical isomerism are:
(A) Propene shows geometrical isomerism.
(B) Trans isomer has identical atoms/groups on the opposite sides of the double bond.
(C) Cis-but-2-ene has higher dipole moment than trans-but-2-ene.
(D) 2-methylbut-2-ene shows two geometrical isomers.
(E) Trans-isomer has lower melting point than cis isomer.
Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II): are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below: