In the reaction \(^2_1H+^3_1H\) \(\rightarrow\) \(^4_2He+^1_0n,\) if the binding energies of \(^2_1H\), \(^3_1H\) and \(^4_2He\) are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is:
c+a-b
c-a-b
a+b+c
a+b-c
The Correct Option is B
Solution and Explanation
we have \(^2_1H+^3_1H\) \(\rightarrow\) \(^4_2He+^1_0n,\)
Energy released, E = (△m)×931MeV
atomic mass unit = 931MeV
\(\triangle\)m=mass of product− mass of reactant
\(\triangle\)m=c−a−b
E=(\(\triangle\)m)×931
i. e ,E =(c−a−b)
The binding energies of \(^2_1H, ^3_1H\) and \(^4_2He\) are respectively a,b and c
Therefore, the correct answer is (B): c-a-b
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Concepts Used:
Nuclei
In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
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Following are the terms related to nucleus:
- Atomic Number
- Mass Number
- Nuclear Size
- Nuclear Density
- Atomic Mass Unit