In the plot of log $ \frac{x}{m} $ $ vs \, log \, p $ for an adsorption, a straight line inclined at an angle of $ \theta=14.04^{\circ} $ to the $ x $-axis was obtained. The $'n'$ value for this adsorption process is $ ( tan \, 14.04^{\circ}=0.25) $
- $ 5 $
- $ 8 $
- $ 4 $
- $ 2 $
The Correct Option is C
Solution and Explanation
slope $=\frac{1}{n}$
Also, slope $=tan\, \theta=tan\, 14.04^{\circ}=0.25$
$\Rightarrow \frac{1}{n}=0.25$
or $n=4$
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Concepts Used:
Surface Chemistry
The study of the chemical phenomena that occur at the interface of two surfaces which can be solid-liquid, solid-gas, solid-vacuum, liquid-gas, etc.
Read Also: Surface Chemistry
Applications of surface chemistry are:
Adsorption:
The process of attraction and aggregation of the molecules of a substance on the surface of a solid is known as adsorption. For Example, N2 adsorbs on the surface of activated charcoal
Two types of adsorption are:-
- Chemisorption: It is also known as Chemical Adsorption.
- Physisorption: It is also known as Physical Adsorption.
Corrosion:
The process through which the refined metals convert themselves into more stable compounds is known as corrosion.
Crystallisation:
The type of technique used in order to purify the substances to separate Solids from liquids is known as crystallisation.
Heterogeneous Catalysis:
The process wherein a catalyst is used in order to increase the rate of a chemical reaction is known as catalysis. The catalyst does not undergo any transformation and can be recovered in a chemically unchanged state.
There are two types of catalysis:-
- When the catalyst involved and the reacting substances are same states of matter or in the same phase, it is known as Homogeneous Catalysis.
- When the catalyst involved and the reacting substances are in different states of matter or different phases, it is known as Heterogeneous Catalysis.