Question:
In the group $G = \{1, 5, 7, 11\}$ under $\otimes_{12}$ the value of $7 \otimes_{12} 11^{-1}$ is equal to
In the group $G = \{1, 5, 7, 11\}$ under $\otimes_{12}$ the value of $7 \otimes_{12} 11^{-1}$ is equal to
Updated On: May 11, 2024
- 5
- 7
- 11
- 1
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The Correct Option is A
Solution and Explanation
$G = \{1, 5, 7,11\}, \oplus_{12}$
we know that 1 is an identity element.
inverse of 11 is,
$11 \oplus_{12} 11^{-1} = 1$ and $11 \oplus_{12} 11 = 1$
Hence $11^{-1} = 11. \therefore \, 7 \oplus_{12} 11^{-1} = 7 \oplus_{12} 11 = 5$
we know that 1 is an identity element.
inverse of 11 is,
$11 \oplus_{12} 11^{-1} = 1$ and $11 \oplus_{12} 11 = 1$
Hence $11^{-1} = 11. \therefore \, 7 \oplus_{12} 11^{-1} = 7 \oplus_{12} 11 = 5$
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Concepts Used:
Relations and functions
A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.
A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.
Representation of Relation and Function
Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.
- Set-builder form - {(x, y): f(x) = y2, x ∈ A, y ∈ B}
- Roster form - {(1, 1), (2, 4), (3, 9)}
- Arrow Representation
