In the given reaction Product A is:
In the given reaction Product A is:
(A)
(B)
(C)
(D)
The Correct Option is D
Solution and Explanation
When the given compound is treated with aqueous KOH, an arenium ion is formed, which is then rearranged (by methyl shift) to give a more stable tertiary carbocation and then nucleophile -OH attacks on the carbonation.The reaction sequence is:
Hence, the correct option is (D).
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