




The problem involves a sequence of reactions that transform compound 'A' into compound 'B'. Let's analyze the steps to determine the structure and chirality of compound 'B'.
Step 1: Formation of Grignard Reagent
The first step involves the reaction of compound 'A' with magnesium (Mg) in the presence of diethyl ether (Et2O). This is a typical method to form a Grignard reagent. The bromine atom in compound 'A' is replaced by a magnesium-bromide (MgBr) unit:

Step 2: Reaction with D2O
In the second step, the Grignard reagent reacts with D2O (deuterium oxide). Grignard reagents are highly reactive with protic solvents like water and deuterium oxide. The deuterium from D2O replaces the magnesium-bromide group, resulting in the formation of a deuterated compound.
The overall reaction can be summarized as the introduction of a deuterium (D) atom in place of the bromine atom:

Conclusion: Structure and Chirality of Compound 'B'
Compound 'B' is a deuterated isobutane. The introduction of deuterium does not create a new chiral center; therefore, the compound remains achiral.
Out of the provided options, this analysis aligns with the option that shows isobutane with D in place of the Br group, having no chiral center.

The product of hydrolysis of propyne in the presence of 1% \( HgSO_4 \) and 40% \( H_2SO_4 \) is ___________.
The structures of major products A , B and C in the following reaction are sequence

The IUPAC name of the following compound is:

Which of the following is the correct IUPAC name of the given organic compound (X)?
The structure of compound $ X $ is as follows:
$ \text{H}_3\text{C} - \text{CH}_3 - \text{CH} = \text{CH} - \text{H} - \text{Br} $
A sub-atomic particle of mass \( 10^{-30} \) kg is moving with a velocity of \( 2.21 \times 10^6 \) m/s. Under the matter wave consideration, the particle will behave closely like (h = \( 6.63 \times 10^{-34} \) J.s)
In organic chemistry, an alkyne is an unsaturated hydrocarbon containing at least one carbon-carbon triple bond. Alkynes are an organic molecule that contains triple bonds between the carbon atoms. Its general formula is CnH2n-2. They are also known as acetylenes. In this article, we will deal with the structure of alkynes.
Alkynes show three types of isomerism