Analyzing the circuit:
1. The AND gate at \( y_1 \):
\[
y_1 = B \cdot C
\]
Substituting \( B = 1 \) and \( C = 1 \):
\[
y_1 = 1 \cdot 1 = 1
\]
2. The NOT gate inverts \( A \):
\[
A' = \overline{A} = \overline{1} = 0
\]
3. The OR gate at \( y_2 \) has inputs \( A' \) and \( y_1 \):
\[
y_2 = A' + y_1
\]
Substituting values:
\[
y_2 = 0 + 1 = 1
\]
Thus, the final values are:
\[
y_1 = 0, \quad y_2 = 1
\]
Thus, the correct answer is \( 0, 1 \).