In the given circuit the input voltage Vin is shown in figure. The cut-in voltage of p–n junction diode (D1 or D2) is 0.6 V. Which of the following output voltage (V0) waveform across the diode is correct?
To determine the correct output voltage waveform across the diode in the given circuit, we need to analyze how the diodes D1 and D2 behave given the input voltage Vin and their cut-in voltage of 0.6 V.
Initial Consideration:
The diodes are connected in parallel, facing opposite directions. D1 is forward-biased when the input voltage is positive, while D2 will be forward-biased when the input voltage is negative.
Analysis for Positive Half Cycle (t > 0):
When Vin > 0, D1 becomes forward-biased if Vin exceeds 0.6 V.
Once D1 conducts, the output voltage V0 will be approximately 0.6 V (cut-in voltage).
Analysis for Negative Half Cycle (t < 0):
When Vin < 0, D2 becomes forward-biased if the negative of Vin exceeds 0.6 V.
Once D2 conducts, the output voltage V0 will be approximately -0.6 V (negative cut-in voltage).
Resulting Output:
The waveform for the output voltage V0 will be a clipped waveform with the limits at +0.6 V and -0.6 V, as the diodes allow clipping at these thresholds.
Therefore, the correct waveform that represents V0 is given by an output that is clipped at +0.6 V during the positive cycle and -0.6 V during the negative cycle.
This image represents the correct waveform for the output V0.
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Approach Solution -2
The correct answer is (D) : Till \(|V|≤0.6 V\) \(|V_0|=|V|\) Therefore, correct graph will be D.
Diodes are used in many applications. By removing the signal component, several of them convert AC current to DC current also are known as rectifiers when used in this position. Diodes act as electric switches and can block voltage spikes, making them ideal for surgical protectors. They are hired to do digital logic. Some things are made from diodes such as power supply and voltage doubles. The sensors, as well as light on lighting devices and lasers, depend on LEDs. For electronic tuning, varactors are used, and for compressing transients in AC lines varistors are used. Zener diodes are used as voltage regulators where varactors are used for electronic tuning, and varistors are used for compressing transients in AC lines.
On the base of diodes, transistors and op-amps are built. The most common diode mode is the p-n junction. One (n) object with electrons as the charging conductor closes the second object (p) with holes (well-charged particles acted as depleted areas of electrons) as the charge carriers on this type of diode. Where they connect, the narrowing space forms, where electrons are dispersed to fill holes in the p-side. This effectively stops the flow of electrons. When a positive voltage is given to the p-side of this junction, electrons may easily move from it and the current flows into the diode to fill the holes. The shrinkage area expands as the negative bias interacts (i.e., negative voltage is given to the p-side), making the electrons harder to move across.
