Question

In the following reaction
\(aX\rightarrow bY\ \ log_{10}(\frac{dx}{dt})=log_{10}(\frac{dy}{dt})+0.4771\)
X and Y respectively can be
[Given: log3=0.4771]

• A. C₂H₂ and C₆H₆
• B. Pentane and 2, 2-Dimethylpropane
• C. O₂ and O₃
• D. N₂O₄ and NO₂

Answer 1

The Correct Option is A

The correct option is (A) : C₂H₂ and C₆H₆