Question

If DASH is 2a84, then SMASH is?

• A. : 7 5 U 7 t
• B. : e y a 8 4
• C. : 8 z q e 3
• D. : 8 z q e 4
• A. : z 6 4 e 4 7 6 c
• B. : z 6 4 e 4 7 6 c
• C. : c 6 7 4 e 4 6 2
• D. : c 6 7 4 e 2 4 6
• A. : w h 7 c d w
• B. : w h 7 6 c v
• C. : b r 7 6 c b
• D. : w h 7 6 c b

Answer 1

The Correct Option is C

Using the table: \[ \begin{array}{c|cccccccccccccccccccccccc} \text{Letter} & A & B & C & D & E & F & G & H & I & J & K & L & M & N & O & P & Q & R & S & T & U & V & W & X & Y & Z
\text{Code} & u & a & 2 & v & b & w & 3 & t & 4 & x & y & 5 & z & 6 & c & d & 8 & 7 & e & r & h & 9 & l & p & q
\end{array} \] DASH becomes: D → v, A → u, S → e, H → t → From question, it's 2a84. So: D → 2, A → a, S → 8, H → 4 Similarly, for SMASH: S → 8, M → z, A → q, S → e, H → 3 So the correct code is: 8 z q e 3

Answer 2

We use the same code table. From the question: F → z, A → 6, S → 4, H → t, I → 7, O → w, N → ? Hence: P → z
O → 6
S → 4
I → e
T → 4
I → 7
O → 6
N → c
Thus, POSITION → z 6 4 e 4 7 6 c

Answer 3

From the code table: E → w
U → h
R → 7
O → 6
P → c
E → w
But in the options, E → w and the last code is v — a mismatch? Let's verify: P → c
O → 6
R → 7
U → h
E → w Matching the full sequence: E U R O P E → w h 7 6 c v (as per option B) → this fits correct mappings.