Step 1: Carbon 'a' (\(CH_3\)) is bonded to 4 other atoms via single sigma bonds. Total \(\sigma\) bonds = 4, so it is sp³ hybridized.
Step 2: Carbon 'b' is part of a triple bond (\(C \equiv C\)). It has 2 \(\sigma\) bonds (one to Carbon 'a', one to Carbon 'c'). Total \(\sigma\) bonds = 2, so it is sp hybridized.
Step 3: Carbon 'c' is also part of the triple bond and has 2 \(\sigma\) bonds (one to Carbon 'b', one to Hydrogen). Total \(\sigma\) bonds = 2, so it is sp hybridized.