Question:

In the following molecule,

Hybridisation of Carbon a, b and c respectively are :

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Shortcut: Single bonds only $\rightarrow$ sp³; One double bond $\rightarrow$ sp²; One triple bond or two cumulative double bonds $\rightarrow$ sp.
Updated On: Feb 2, 2026
  • sp³, sp², sp²
  • sp³, sp, sp
  • sp², sp, sp²
  • sp³, sp, sp
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The Correct Option is B

Solution and Explanation

Step 1: Carbon 'a' (\(CH_3\)) is bonded to 4 other atoms via single sigma bonds. Total \(\sigma\) bonds = 4, so it is sp³ hybridized.
Step 2: Carbon 'b' is part of a triple bond (\(C \equiv C\)). It has 2 \(\sigma\) bonds (one to Carbon 'a', one to Carbon 'c'). Total \(\sigma\) bonds = 2, so it is sp hybridized.
Step 3: Carbon 'c' is also part of the triple bond and has 2 \(\sigma\) bonds (one to Carbon 'b', one to Hydrogen). Total \(\sigma\) bonds = 2, so it is sp hybridized.
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